# Line slope calculator 8x+3y=62

**Straight line given by points A[4; 10] and B[7; 2]**

## Calculation:

**Slope-intercept form of line:**y = -2.6667x+20.6667

**Canonical form of the line equation:**8x+3y-62 = 0

**Parametric form of the line equation:**

x = 3t+4

y = -8t+10 ; t ∈ R

**Slope:**m = -2.6667

**Slope angle of line: φ =**-69°26'38″ = -1.212 rad

**X intercept:**x

_{0}= 7.75

**Y intercept:**y

_{0}= q = 20.6667

**Distance line from the origin:**d

_{0}= 7.2566

**The length of the segment AB: |AB| =**8.544

**Vector: AB =**(3; -8)

**Normal vector: n =**(8; 3)

**Midpoint of the segment AB: M =**[5.5; 6]

**Perpendicular Bisector equation:**3x-8y+31.5 = 0

**Vector OA = (4; 10) ; |OA| = 10.7703**

**Vector OB = (7; 2) ; |OB| = 7.2801**

**Scalar product OA .OB = 48**

**Angle ∠ AOB = 52°15'11″ = 0.912 rad**