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Acids and BasesReview Demonstration Kit for AP® Chemistry![]() IntroductionThe course description for the College Board AP® Chemistry lists the following topics for acids and bases: concepts of Arrhenius, Brønsted-Lowry and Lewis, coordination complex, amphoterism, pKa and pH, buffers and hydrolysis. Use this set of three acid–base neutralization demonstrations to engage your students in a hands-on review and test their understanding of this key topic in chemistry.
The series of demonstrations may be presented in a variety of ways. Each demonstration may be used to review a specific AP test topic, or all the demonstrations can be performed together as a review student understanding and grasp of stoichiometry concepts normally covered in the AP exam. A student worksheet is included as an optional assessment tool for the instructor. Concepts
Experiment OverviewActivity 1. Weak Acid–Weak Base Titration MaterialsActivity 1. Weak Acid–Weak Base Titration Safety PrecautionsPhenolphthalein is moderately toxic by ingestion. Universal indicator solution is slightly toxic by ingestion. All the carboxylic acid solutions are corrosive liquids and body tissue irritants. The sodium hydroxide solution is corrosive to skin and eyes and is also a body tissue irritant. Avoid contact with eyes and skin and clean up all spills immediately. Wear chemical splash goggles, chemical-resistant gloves and a chemical-resistant apron. Please consult current Safety Data Sheets for additional safety, handling and disposal information. DisposalPlease consult your current Flinn Scientific Catalog/Reference Manual for general guidelines and specific procedures, and review all federal, state and local regulations that may apply, before proceeding. Remaining solutions may be neutralized and flushed down the drain with excess water. Prelab PreparationActivity 2. Titrating an Acid Mixture
ProcedureActivity 1. Weak Acid–Weak Base Titration
Activity 2. Titrating an Acid Mixture
Activity 3. Acid Strength and Electron Withdrawing Groups
Student Worksheet PDFTeacher Tips
Sample DataActivity 3. Acid Strength {12161_Data_Table_1}
Indicator Chart
{12161_Data_Table_2}
Answers to QuestionsActivity 1. Weak Acid–Weak Base Titration
Record the titration data, then graph volume of NaOH added versus pH. {12161_Answers_Figure_4}
Activity 3. Acid Strength
DiscussionActivity 1. Weak Acid–Weak Base Titration {12161_Discussion_Figure_6}
The steepness of the curve and the pH value at the equivalence point depend on the strength of both the acid and the base. If both the acid and base are strong, the curve is very steep and the equivalence point pH value is 7. If a weak acid is titrated by a strong base, the titration curve is less steep and the equivalence point pH value is >7. At the equivalence point, assuming the acid is monobasic (HA).
{12161_Discussion_Equation_5}
or
{12161_Discussion_Equation_6}
The overall neutralization reaction is,
{12161_Discussion_Equation_7}
At this point, the initial moles of the weak acid (HA) have been completely converted to its conjugate base (A–). This conjugate base is a weak base and equilibrates with water to form a basic solution.
{12161_Discussion_Equation_8}
Kb for this reaction is,
{12161_Discussion_Equation_9}
The story for a weak base is similar. The conjugate acid of a weak base produces an acidic solution at the equivalence point when titrated with a strong acid.
{12161_Discussion_Equation_10}
{12161_Discussion_Equation_11}
What happens at the equivalence point when a weak base is titrated with a weak acid? For a weak acid with a dissociation constant Ka' the value of Kb' for its conjugate base is:
{12161_Discussion_Equation_12}
For a weak base with a dissociation constant of Kb, the value of Ka for its conjugate acid is:
{12161_Discussion_Equation_13}
Combining Equations 12 and 13 yields:
{12161_Discussion_Equation_14}
If Ka' of the weak acid is greater than Kb of the weak base, then Ka is greater than Kb'. The pH of the solution at the equivalence point is acidic. If Kb of the weak base is greater than Ka' of the weak acid, the pH of the solution at the equivalence point is basic.Activity 2. Titrating an Acid Mixture Dealing with a mixture of acids seems tricky at first glance. If, for example, you were to titrate a solution of only HCl or diprotic weak acid H2A, it would be a simple matter to determine the concentration of the acid and/or the dissociation constant, Ka, of the weak acid. However, when you titrate an aqueous solution containing both HCl and H2A the task of determining much of anything about the mixture seems quite complex—until you think about equilibrium. Let’s explore the weak diprotic acid in more detail. {12161_Discussion_Equation_20}
Now, when you mix some HCl with a solution of H2A, you are adding a huge amount of H3O+ ions because HCl is a strong acid (dissociates completely). Recall what Le Chatelier had to say about equilibria and you will see that the 1st dissociation equation contains a whole lot of H2A and H3O+ and practically no HA–. This is what your acid mixture looks like before you start the titration. As you titrate the mixture of HCl and H2A with sodium hydroxide, the OH– ions react with H3O+ ions from the HCl and the H2A molecules to reach the 1st equivalence point. On the titration plot, however, there is no way to identify the source of the H3O+ ions up to the 1st equivalence point. But, we’ll be able to figure it out. As the titration continues past the 1st equivalence point, you are now neutralizing the HA– ions. The number of moles of NaOH you add from the 1st eq. pt. to the 2nd eq. pt. is equal to the number of moles of HA– ion. Also, the original amount of H2A in the mixture is equal to the moles of HA– ions (see the 1st dissociation equation). Thus, to calculate the number of moles of HCl in the mixture you subtract the moles of HA– from the moles of NaOH used to reach the 1st eq. pt. From here, calculating the molar concentration of HCl and H2A is simple. That piece of the puzzle is solved. How do we calculate the Ka2 (or the pKa2) of the diprotic acid? The equilibrium expression for the 2nd dissociation is shown: {12161_Discussion_Equation_15}
If we take the logarithm of both sides of this equation, and do a bit of rearranging, we get the Henderson–Hasselbalch equation:
{12161_Discussion_Equation_16}
In this version of the Henderson-Hasselbalch equation, if the molar concentration of the two ionic species is equal then the pKa2 and the pH are equal. This event occurs exactly halfway between the 1st eq. pt. and the 2nd eq. pt. Thus, you can read the pKa2 of a diprotic acid directly from the titration plot.Here’s an example. The following graph shows the titration of 10.0 mL of a mixture of HCl and maleic acid with 0.10 M NaOH solution. {12161_Discussion_Figure_7}
(0.006 L) x (0.10 mol/L) = 6.0 x 10–4 mol of OH– used between 1st and 2nd eq. pts. ∴6.0 x 10–4 mol of H2A and 6.0 x 10–4 mol of HA– were in the mixture [H2A] = 6.0 x 10–4 mol 0.010 L of total mixture = 0.06 M maleic acid (0.010 L) x (0.10 mol/L) = 0.0010 mol of OH– used to reach the 1st eq. pt. ∴0.0010 mol of H3O+ ions came from HCl + H2A ...and, we know that there were 6.0 x 10–4 mol of H2A ∴mol HCl = 0.0010 mol – 6.0 x 10–4 mol = 4.0 x 10–4 mol [HCl] = 4.0 x 10–4 mol 0.010 L of total mixture = 0.04 M HCl Examine another region of the titration plot to determine the pKa2 of maleic acid. Halfway between the 1st equivalence point and the 2nd equivalence point is the point at which 13.00 mL of NaOH were added. This also corresponds to [A2–] = [HA–]. The pH at this point is 6.07, which is the pKa2 of the diprotic acid, maleic acid. Activity 3. Acid Strength and Electron Withdrawing Groups When an acid dissolves in water, it donates hydrogen ions to water molecules to form H3O+ ions. The general form of this reaction, called an ionization reaction, is shown in Equation 16, where HA is the acid and A– its conjugate base after loss of a hydrogen ion. The double arrows represent a reversible reaction. The equilibrium constant expression (Ka) for the reversible ionization of an acid is given in Equation 17. {12161_Discussion_Equation_17}
{12161_Discussion_Equation_18}
Not all acids, of course, are created equal. The strength of an acid depends on the value of its equilibrium constant Ka for Equation 17. Weak acids ionize only partially in aqueous solution. The value of Ka for a weak acid is much less than one, so that Equation 17 is reversible—all species (HA, A– and H3O+) are present at equilibrium. The three weak acids used in this demonstration are acetic acid, chloroacetic acid and trichloroacetic acid.
{12161_Discussion_Figure_8}
Any factor that stabilizes the conjugate base anion more that the weak acid should increase the strength of the acid and its Ka value. Electron-withdrawing groups, such as chlorine atoms, disperse the negative charge on the conjugate base anion and thus stabilize the anion relative to the acid (see Figure 9). In fact, chloroacetic acid is on the order of 100 times stronger than acetic acid, and trichloroacetic acid is more than 30,000 times stronger! The arrows in Figure 9 are meant to indicate the electron withdrawing nature of the chlorine atoms.
{12161_Discussion_Figure_9}
The ionization constant of a weak acid can be determined experimentally by measuring the H3O+ concentration in a dilute aqueous solution of the weak acid. This procedure is most accurate when the solution contains equal molar amounts of the weak acid and its conjugate base. If the concentrations of the weak acid [HA] and the conjugate base [A–] are equal, then these two terms cancel out in the equilibrium constant expression, and Equation 18 reduces to Equation 19.
{12161_Discussion_Equation_19}
The half-neutralized pH values for the three weak acids are:
Acetic acid pH = 4.75 Recommended Products |