Teacher Notes
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Teacher Notes![]() Stoichiometry... Can You Make 2.00 Grams of a Compound?Student Laboratory KitMaterials Included In Kit
Calcium acetate monohydrate, Ca(C2H3O2)2•H2O, 65 g
Calcium chloride dihydrate, CaCl2•2H2O, 60 g Magnesium sulfate heptahydrate, Mg(SO4)2•7H2O, 100 g Potassium carbonate, K2CO3, 60 g Sodium carbonate, Na2CO3, 50 g Zinc sulfate heptahydrate, ZnSO4•7H2O, 100 Student and teacher instructions Additional Materials Required
Balance to measure to 0.01 g
Beakers, 100-mL, 2 per lab group Filtration setup* Filter paper, 1 per lab group Heat lamp or drying oven *See Figure 1a or 1b in Prelab Preparation. Prelab PreparationFigure 1a: How to Set Up a Gravity Filtration
Safety PrecautionsThe six chemicals provided in this kit were selected because of their relatively low toxicity levels and ease of disposal. Zinc sulfate is a skin and mucous membrane irritant and mildly toxic. Sodium carbonate and potassium carbonate may be skin irritants. Magnesium sulfate irritates eyes and respiratory tract. Calcium chloride is moderately toxic. Wear chemical splash goggles, chemical-resistant gloves and chemical-resistant aprons. Please review current Safety Data Sheets for additional safety, handling and disposal information DisposalPlease consult your current Flinn Scientific Catalog/Reference Manual for general guidelines and specific procedures, and review all federal, state and local regulations that may apply, before proceeding. All solids can be buried in a landfill site approved for the disposal of chemical and hazardous wastes, following the Flinn Disposal Method #26a. Solutions can be simply poured down the drain if your school is connected to a sanitary sewer system with a water treatment plant according to Flinn Disposal Method #26b. Teacher Tips
Correlation to Next Generation Science Standards (NGSS)†Science & Engineering PracticesAsking questions and defining problemsPlanning and carrying out investigations Analyzing and interpreting data Using mathematics and computational thinking Constructing explanations and designing solutions Disciplinary Core IdeasHS-PS1.B: Chemical ReactionsHS-PS2.B: Types of Interactions HS-ETS1.A: Defining and Delimiting Engineering Problems HS-ETS1.B: Developing Possible Solutions HS-ETS1.C: Optimizing the Design Solution Crosscutting ConceptsPatternsScale, proportion, and quantity Energy and matter Stability and change Performance ExpectationsHS-PS1-3. Plan and conduct an investigation to gather evidence to compare the structure of substances at the bulk scale to infer the strength of electrical forces between particles. Answers to Prelab QuestionsSample Problem
Work Space
{12518_PreLab_Equation_10}
Teacher HandoutsReferencesSpecial thanks to Mark A. Case from Emmaus High School, Emmaus, PA, for developing this laboratory procedure. Recommended Products |
Student Pages
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Student Pages![]() Stoichiometry... Can You Make 2.00 Grams of a Compound?IntroductionUse your skills of predicting chemical reactions, balancing equations and calculating molar mass to solve a complex stoichiometry problem. Then test your laboratory techniques by mixing the reactants and isolating exactly 2.00 g of a compound. Concepts
BackgroundStoichiometry is the branch of chemistry that deals with the numerical relationships and mathematical proportions of reactants and products in chemical reactions. For any chemical equation the mole, mass, and atom ratios must remain constant. The coefficients from a balanced chemical equation provide definite ratios between the number of moles of reactants and products involved (Equation 1). {12518_Background_Equation_1}
One mole of any chemical substance contains 6.02 x 1023 particles (e.g., molecules, atoms) and has a mass equal to the sum of atomic weights of all elements in the formula. Therefore, the mole ratio of a balanced chemical equation can be converted into a mass ratio or number of particles ratio. These ratios can be used as conversion factors to determine the exact amounts of reactants that combine and products that form during a chemical change (Equation 2).
{12518_Background_Equation_2}
When two ionic compounds are placed in solution, a double replacement reaction can occur. Double replacement reactions are also called double displacement or exchange reactions and follow the pattern: A+X– + B+Y– → B+X– + A+Y–. Normally, the reactants are chosen so one product will precipitate out of solution while the other ions stay in solution. In this way, one of the products can be easily isolated by filtration. Equation 3 is an example of a double replacement reaction.
{12518_Background_Equation_3}
When the reacting ionic compounds are dissolved in water, they separate into the four different ions that are free to move around and then recombine to form the new products. If one of the combination of ions is insoluble in water, it will precipitate out of solution. In Equation 3, lead iodide (PbI2) precipitates out of solution. Some ionic solids also contain water molecules that are trapped within their crystal structure. These are called hydrated compounds. An example of a hydrated compound would be copper(II) sulfate pentahydrate, Cu(SO4)•5H2O. During the dissolving process, the water molecules are released into the solution. In order to produce the 2.00 grams of desired product in the laboratory using a double replacement reaction, a balanced equation is required and the product that will precipitate must be identified. The next step is to determine the molar mass of each reactant and product, and finally use dimensional analysis to determine the quantities of reactants required. The following four steps describe the process in detail. Safety PrecautionsThe compounds selected for this experiment have low to moderate toxicity, but avoid breathing the dust or getting any in yours eyes or on your skin. Zinc sulfate is a skin and mucous membrane irritant and is mildly toxic. Sodium carbonate and potassium carbonate may be skin irritants. Magnesium sulfate irritates eyes and the respiratory tract. Calcium chloride is moderately toxic. Wear chemical splash goggles, chemical-resistant gloves and chemical-resistant aprons. ProcedureStep 1. Write a balanced formula equation for the reaction. {12518_Background_Equation_4}
Next, prepare an unbalanced equation by writing out the chemical formula for each reactant and product.
{12518_Background_Equation_5}
Finally, the chemical equation must be balanced. The key principle in balancing equations is that atoms are conserved in a chemical reaction. Therefore, the same number and type of atoms must be found among the reactants and products of a reaction. For example, if you start with two nitrogen atoms in the reactants, you must have two nitrogen atoms in the products.
{12518_Background_Equation_6}
Most chemical equations can be balanced by trial and error. This is done by adding up the quantity of each atom present on the reactants side of the equation and on the product side of the equation. Identify which atoms are not balanced and determine what coefficients are necessary in front of one of the reactants or products to balance the quantity of that atom on both sides of the equation.Step 2. Predict which compound will form a precipitate using general solubility rules. When working with aqueous solutions, it is helpful to understand a few rules concerning which substances are soluble in water and which will form precipitates. The more common solubility rules are listed:
Step 3. Calculate the mass of reactants needed to produce the 2.00 g of precipitate. To calculate the mass of reactants needed to produce 2.00 g of a precipitated product requires the determination of the molar mass of each reactant and product. Molar mass (also called molecular weight) is the mass in grams of one mole of a substance. Molar mass is determined by adding the atomic masses of all of the atoms in the chemical formula. For example, the chemical formula CuSO4•5H2O shows that in 1 mole of this compound, there are 1 mole of Cu ions, 1 mole of SO4 ions and 5 moles of H2O, which gives a total of 1 mole of Cu, 1 mole of S, 10 moles of H and 9 moles of O atoms. The total mass of each element in the compound is equal to the number of moles of atoms of the element multiplied by its atomic mass. The molar mass of copper(II) sulfate pentahydrate is equal to the sum of the total masses of each element: {12518_Background_Table_1}
Once the molar mass of each reactant and product is determined, the next step is to determine the number moles in 2.00 g of precipitate using Equation 7.
{12518_Background_Equation_7}
For example, if 2.00 g of copper(II) sulfate pentahydrate is desired, the number of moles will be: 2.00 g ÷ 249.72 g/mol or 0.00801 moles. Using dimensional analysis, the equations would be:
{12518_Background_Equation_9}
Lastly, use the coefficients in the balanced equation to determine the number of moles of each of the reactants required to produce the desired number of moles of precipitate. Once the number of moles is obtained, use the following equation to calculate the number of grams of each reactant.
{12518_Background_Equation_8}
Step 4. Use the calculated masses of reactants to make and recover the 2.00 grams of precipitate. After the chemical equation is balanced, the precipitated product is determined and the mass of each reactant required to produce 2.00 g of product is calculated, the reaction can be performed in lab. Both of the reactants need to be dissolved in separate beakers using 25 mL of distilled water for each reactant. Then the two solutions need to be mixed together to form the precipitate. The precipitate will be recovered by filtration using a pre-massed piece of filter paper. The precipitate will be dried under a heat lamp or in a drying oven, and then the mass of the solid determined. The precipitate will be turned in to your teacher and the percent error calculated for the experiment. Tips
Student Worksheet PDF |